7 inputs and 8 outputs. only 3 outputs can be TRUE at once

Codesys V2.3 🇬🇧
espenbo
2018-11-15
2018-11-15

  • espenbo - 2018-11-15

    Hello. I need some help with a control function.

    I have 7 switches connected to digital inputs on the PLS and 7 Digital outputs.

    Digital input 1 controls Digital Out 1
    Digital input 2 controls Digital Out 2
    Digital input 3 controls Digital Out 3
    Digital input 4 controls Digital Out 4
    Digital input 5 controls Digital Out 5
    Digital input 6 controls Digital Out 6
    Digital input 7 controls Digital Out 7

    When 3 digital outputs are TRUE, no more outputs are allowed to be set to TRUE.
    Then you must turn off an output before the next can be turned on.

    If I set
    Digital input 1 = TRUE
    Digital input 2 = TRUE
    Digital input 3 = TRUE
    Digital input 4 = FALSE
    Digital input 5 = FALSE
    Digital input 6 = FALSE
    Digital input 7 = FALSE
    Then
    Digital out 1 = TRUE
    Digital out 2 = TRUE
    Digital out 3 = TRUE
    Digital out 4 = FALSE
    Digital out 5 = FALSE
    Digital out 6 = FALSE
    Digital out 7 = FALSE

    Then I set Digital 4 TRUE

    Digital input 1 = TRUE
    Digital input 2 = TRUE
    Digital input 3 = TRUE
    Digital input 4 = TRUE
    Digital input 5 = FALSE
    Digital input 6 = FALSE
    Digital input 7 = FALSE
    Then
    Digital out 1 = TRUE
    Digital out 2 = TRUE
    Digital out 3 = TRUE
    Digital out 4 = FALSE
    Digital out 5 = FALSE
    Digital out 6 = FALSE
    Digital out 7 = FALSE

    And nothing should happen to the output

    If I then turn of digital input 1 to FALSE I get

    Digital input 1 = FALSE
    Digital input 2 = TRUE
    Digital input 3 = TRUE
    Digital input 4 = TRUE
    Digital input 5 = FALSE
    Digital input 6 = FALSE
    Digital input 7 = FALSE
    Then
    Digital out 1 = FALSE
    Digital out 2 = TRUE
    Digital out 3 = TRUE
    Digital out 4 = TRUE
    Digital out 5 = FALSE
    Digital out 6 = FALSE
    Digital out 7 = FALSE

    I Then turn Digital input 5 to TRUE and digital input 2 to FALSE.
    Digital output 2 don't go to FALSE

    Digital input 1 = FALSE
    Digital input 2 = FALSE
    Digital input 3 = TRUE
    Digital input 4 = TRUE
    Digital input 5 = TRUE
    Digital input 6 = FALSE
    Digital input 7 = FALSE
    Then
    Digital out 1 = FALSE
    Digital out 2 = TRUE
    Digital out 3 = TRUE
    Digital out 4 = TRUE
    Digital out 5 = FALSE
    Digital out 6 = FALSE
    Digital out 7 = FALSE

    How can I get thise to work?

    VAR_GLOBAL CONSTANT
   IOMAXSIZE: INT := 7;
END_VAR
PROGRAM test2
VAR
    aInput         : ARRAY[1..IOMAXSIZE] OF BOOL;
    aOutput         : ARRAY[1..IOMAXSIZE] OF BOOL;
    aINT_Input      : ARRAY[1..IOMAXSIZE] OF INT;
    aINT_Output      : ARRAY[1..IOMAXSIZE] OF INT;
    iCount         : INT;
   iTotalInput      : INT;
   iTotalOutput   : INT;
END_VAR
(*Max 3 til TRUE samtidig. Alle de andre skal da være stengt.
Ikke mulig å åpne den 4 når 3 allerede er TRUE.
Bør kunne gå fra 4 innganger i TRUE til 3 UTGANGER i TRUE direkte. Ikke måtte innom kun 2 i TRUE*)
PROG
   (*Legger sammen alle utgangene som er TRUE en total variabel*)
   iTotalInput := aINT_Input[1] + aINT_Input[2] + aINT_Input[3] + aINT_Input[4] + aINT_Input[5] + aINT_Input[6] + aINT_Input[7];
   iTotalOutput := aINT_Output[1] + aINT_Output[2] + aINT_Output[3] + aINT_Output[4] + aINT_Output[5] + aINT_Output[6] + aINT_Output[7];
(*Gjør om fra BOOL verdier til INT*)
FOR iCount := 1 TO IOMAXSIZE BY 1 DO
   aINT_Input[iCount] := BOOL_TO_INT (aInput[iCount]);
   aINT_Output[iCount] := BOOL_TO_INT (aOutput[iCount]);
END_FOR
(*Hvis det er mindre en 3 innganer som er på kjøres denne*)
IF (iTotalInput < 3) THEN
   (*Overfører utganger til ingangs arrayene*)
   FOR iCount := 1 TO IOMAXSIZE BY 1 DO
      aOutput[iCount] := aInput[iCount];
   END_FOR
END_IF
(*Her er tanket at Hvis det er 3 Innganger som er TRUE, men disse ikke sammsvarer med utgangene som er TRUE.
Så kjør denne for å oppdatere innganger å utganger*)
IF (iTotalInput = 3) AND NOT aOutput[iCount] = aInput[iCount] THEN
   FOR iCount := 1 TO IOMAXSIZE BY 1 DO
      aOutput[iCount] := aInput[iCount];
   END_FOR
END_IF

    Link to video
    https://www.dropbox.com/s/opu2b96l5lvhl ... 5.MOV?dl=0

    Link to program
    https://www.dropbox.com/s/qz1jtw7bse6cfaq/test.zip?dl=0 m

     

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  • Lo5tNet - 2018-11-15

    There are two problems I see that once fixed will get your function to work properly.

    Try using this code instead and you can compare to what you have to see what has changed.

    (*Gjør om fra BOOL verdier til INT*)
FOR iCount := 1 TO IOMAXSIZE BY 1 DO
   aINT_Input[iCount] := BOOL_TO_INT (aInput[iCount]);
   aINT_Output[iCount] := BOOL_TO_INT (aOutput[iCount]);
END_FOR
(*Legger sammen alle utgangene som er TRUE en total variabel*)
   iTotalInput := aINT_Input[1] + aINT_Input[2] + aINT_Input[3] + aINT_Input[4] + aINT_Input[5] + aINT_Input[6] + aINT_Input[7];
   iTotalOutput := aINT_Output[1] + aINT_Output[2] + aINT_Output[3] + aINT_Output[4] + aINT_Output[5] + aINT_Output[6] + aINT_Output[7];
(*Hvis det er mindre en 3 innganer som er på kjøres denne*)
IF (iTotalInput < 3) THEN
   (*Overfører utganger til ingangs arrayene*)
   FOR iCount := 1 TO IOMAXSIZE BY 1 DO
      aOutput[iCount] := aInput[iCount];
   END_FOR
END_IF
(*Her er tanket at Hvis det er 3 Innganger som er TRUE, men disse ikke sammsvarer med utgangene som er TRUE.
Så kjør denne for å oppdatere innganger å utganger*)
FOR iCount := 1 TO IOMAXSIZE BY 1 DO
   IF (iTotalInput = 3) AND aOutput[iCount] <> aInput[iCount] THEN
      aOutput[iCount] := aInput[iCount];
   END_IF
END_FOR

    The first problem was was you were counting inputs of aINT_Input then later assigning the values you were changing so the iTotalInput value was wrong.
    The second problem was the last if/for statements that were made needed to be done in a different order. The IF statement was only checking to see if aInput[iCount] of array position 8 did not equal aOutput[iCount] of array position 8. The IF statement needed to be moved into the FOR loop in order to iterate through the array using the iCount variable.

     

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  • espenbo - 2018-11-15

    Thank you for youre feedback Comingback4u

    I been working with it and found another solution.

    PROGRAM test2
VAR
    aInput         : ARRAY[1..IOMAXSIZE] OF BOOL;
    aOutput         : ARRAY[1..IOMAXSIZE] OF BOOL;
    aINT_Input      : ARRAY[1..IOMAXSIZE] OF INT;
    aINT_Output      : ARRAY[1..IOMAXSIZE] OF INT;
    iCount         : INT;
   iTotalInput      : INT;
   iTotalOutput   : INT;
   iTotalActiveInputs: INT;
   iInputCount: INT;
   bad: BOOL;
END_VAR
(*Teller opp antall inputer som er TRUE*)
iTotalActiveInputs := 0;
FOR iInputCount := 1 TO IOMAXSIZE BY 1 DO
   IF (aInput[iInputCount] = TRUE) THEN
      iTotalActiveInputs := iTotalActiveInputs + 1;
   END_IF
END_FOR
(*Hvis det er mindre en 4 inputer som er TRUE, overfør inputer mot outputene*)
FOR iCount := 1 TO IOMAXSIZE BY 1 DO
   IF (iTotalActiveInputs < 4) THEN
      aOutput[iCount] := aInput[iCount];
(*Hvis det er 0 inputs som er TRUE set outputene til FALSE*)
   ELSIF (iTotalActiveInputs = 0) THEN
      aOutput[iCount] := FALSE;
   END_IF
   aINT_Input[iCount] := BOOL_TO_INT (aInput[iCount]);
   aINT_Output[iCount] := BOOL_TO_INT (aOutput[iCount]);
END_FOR
(* DEN ULTIMATE TEST *)
IF (iTotalActiveInputs < 4) THEN
   FOR iCount := 1 TO IOMAXSIZE BY 1 DO
      IF (aOutput[iCount] <> aInput[iCount]) THEN
         bad := TRUE;
      END_IF
   END_FOR
END_IF

    Link to project
    https://www.dropbox.com/s/h6kgatk13g2x0 ... n.zip?dl=0

    I will test the code to try to learn more about how this can be solved.

     

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