Hey,
i will display a graph on the xy_chart. That works pretty nice, only the one line in the Picture from (0,0) to the third quarter is bothering me.
that is the Skrip for the graph.
VL_global.X_Array[zahler2]:=-10+zahler1;
IF VL_global.Referenzkorrektur_alt>=-1 THEN
VL_global.Y_Array[zahler2]:=-(EXPT(VL_global.X_Array[zahler2]/1.2,2))+VL_global.Referenzkorrektur_alt;
END_IF
IF VL_global.Referenzkorrektur_alt<0 THEN
VL_global.Y_Array[zahler2]:=(EXPT(VL_global.X_Array[zahler2]/1.2,2))+VL_global.Referenzkorrektur_alt;
END_IF
Had anyone a solution to delete the little line?
greeting
Moritz
Hi,
check the values inside array, probably some of them could be the problem. It seems the value 0,0 is the initial point of this line. Check if there is any value in array with 0,0.
BR
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Hey,
i will display a graph on the xy_chart. That works pretty nice, only the one line in the Picture from (0,0) to the third quarter is bothering me.
that is the Skrip for the graph.
VL_global.X_Array[zahler2]:=-10+zahler1;
IF VL_global.Referenzkorrektur_alt>=-1 THEN
VL_global.Y_Array[zahler2]:=-(EXPT(VL_global.X_Array[zahler2]/1.2,2))+VL_global.Referenzkorrektur_alt;
END_IF
IF VL_global.Referenzkorrektur_alt<0 THEN
VL_global.Y_Array[zahler2]:=(EXPT(VL_global.X_Array[zahler2]/1.2,2))+VL_global.Referenzkorrektur_alt;
END_IF
Had anyone a solution to delete the little line?
greeting
Moritz
Hi,
check the values inside array, probably some of them could be the problem. It seems the value 0,0 is the initial point of this line. Check if there is any value in array with 0,0.
BR