Let me see if I understand what you're saying here. You have two bytes, lower and upper. For the low byte, you are interested in bits 2-7; everything for the high byte.

Assuming %IB10 is your low byte and %IB11 is your high byte

uiOutput : UINT;

// to always ignore the last two bits of the low byte
// using 16#FC for masking since it is 11111100
uiOutput := SHL(TO_UINT(%IB11), 8) OR (%IB10 AND 16#FC);

// to shift right the 2 least significant bits
// i.e. 11111111 becomes 00111111
uiOutput := SHL(TO_UINT(%IB11), 8) OR SHR(%IB10, 2);

@dsongra,

Thanks for the Conversion info.png. This makes more sense and it is probably why you are not seeing the result. It looks like we would need to generate the uint from the byte pairs and then shift. Try this instead:

// generate uint from byte pair
uiOutput := SHL(TO_UINT(%IB10), 8) OR %IB11;
// shift right by 2
uiOutput := SHR(uiOutput, 2);

We also swapped %IB10 (previously low byte) and %IB11 (previously high byte) data starts with most significant bit (MSB) from data sheet. Doing rough math, 3 (16#03) 40 (16#28) yields (808) 16#0328. We take this and shift right by 2 bits, or effectively divide by 4; thus resulting in 202. My first guess would be 20.2 cm or 202 mm?